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Portable Network Graphic  |  1993-02-04  |  2KB  |  512x342  |  1-bit (2 colors)
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OCR: Solution: In the triangle formed by the station, the satellite, and the center of Earth, Y = 1200. From the law of sines. sin ox sin Y 6400 8000 sin c = 6400 sin1200 8000 = 0.693 Then X= 440 and 3 = 1800 - (1200 + 44º) = 16º The time between B = 16º and B = 0.00 is 160 3600 (120 min) = 5.3 min. This means that the satellite will pass through the beam of the antenna at 12:00 - 5.3 minutes, or 11:54.7 a.m. (See next card.)